8(y-3)+4(y+1)=52

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Solution for 8(y-3)+4(y+1)=52 equation: 



8(y-3)+4(y+1)=52

We move all terms to the left:

8(y-3)+4(y+1)-(52)=0

We multiply parentheses

8y+4y-24+4-52=0

We add all the numbers together, and all the variables

12y-72=0

We move all terms containing y to the left, all other terms to the right

12y=72

y=72/12

y=6

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