8(y-3)+8=4(y+12)

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Solution for 8(y-3)+8=4(y+12) equation:


Simplifying
8(y + -3) + 8 = 4(y + 12)

Reorder the terms:
8(-3 + y) + 8 = 4(y + 12)
(-3 * 8 + y * 8) + 8 = 4(y + 12)
(-24 + 8y) + 8 = 4(y + 12)

Reorder the terms:
-24 + 8 + 8y = 4(y + 12)

Combine like terms: -24 + 8 = -16
-16 + 8y = 4(y + 12)

Reorder the terms:
-16 + 8y = 4(12 + y)
-16 + 8y = (12 * 4 + y * 4)
-16 + 8y = (48 + 4y)

Solving
-16 + 8y = 48 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-16 + 8y + -4y = 48 + 4y + -4y

Combine like terms: 8y + -4y = 4y
-16 + 4y = 48 + 4y + -4y

Combine like terms: 4y + -4y = 0
-16 + 4y = 48 + 0
-16 + 4y = 48

Add '16' to each side of the equation.
-16 + 16 + 4y = 48 + 16

Combine like terms: -16 + 16 = 0
0 + 4y = 48 + 16
4y = 48 + 16

Combine like terms: 48 + 16 = 64
4y = 64

Divide each side by '4'.
y = 16

Simplifying
y = 16

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