8(y-3)=2(2y+4)

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Solution for 8(y-3)=2(2y+4) equation: 



8(y-3)=2(2y+4)

We move all terms to the left:

8(y-3)-(2(2y+4))=0

We multiply parentheses

8y-(2(2y+4))-24=0



We calculate terms in parentheses: -(2(2y+4)), so:

2(2y+4)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

8y-4y-8-24=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8

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