8(y-3)=4(2y-6)

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Solution for 8(y-3)=4(2y-6) equation: 



8(y-3)=4(2y-6)

We move all terms to the left:

8(y-3)-(4(2y-6))=0

We multiply parentheses

8y-(4(2y-6))-24=0



We calculate terms in parentheses: -(4(2y-6)), so:

4(2y-6)

We multiply parentheses

8y-24

Back to the equation:

-(8y-24)



We get rid of parentheses

8y-8y+24-24=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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