8(y-3)=4y-32

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Solution for 8(y-3)=4y-32 equation: 



8(y-3)=4y-32

We move all terms to the left:

8(y-3)-(4y-32)=0

We multiply parentheses

8y-(4y-32)-24=0

We get rid of parentheses

8y-4y+32-24=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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