8(y-4)+2(y+2)=62

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Solution for 8(y-4)+2(y+2)=62 equation: 



8(y-4)+2(y+2)=62

We move all terms to the left:

8(y-4)+2(y+2)-(62)=0

We multiply parentheses

8y+2y-32+4-62=0

We add all the numbers together, and all the variables

10y-90=0

We move all terms containing y to the left, all other terms to the right

10y=90

y=90/10

y=9

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