8(y-4)-7=3(2y+1)

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Solution for 8(y-4)-7=3(2y+1) equation: 



8(y-4)-7=3(2y+1)

We move all terms to the left:

8(y-4)-7-(3(2y+1))=0

We multiply parentheses

8y-(3(2y+1))-32-7=0



We calculate terms in parentheses: -(3(2y+1)), so:

3(2y+1)

We multiply parentheses

6y+3

Back to the equation:

-(6y+3)



We add all the numbers together, and all the variables

8y-(6y+3)-39=0

We get rid of parentheses

8y-6y-3-39=0

We add all the numbers together, and all the variables

2y-42=0

We move all terms containing y to the left, all other terms to the right

2y=42

y=42/2

y=21

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