8(y-4)=-4y-20

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Solution for 8(y-4)=-4y-20 equation: 



8(y-4)=-4y-20

We move all terms to the left:

8(y-4)-(-4y-20)=0

We multiply parentheses

8y-(-4y-20)-32=0

We get rid of parentheses

8y+4y+20-32=0

We add all the numbers together, and all the variables

12y-12=0

We move all terms containing y to the left, all other terms to the right

12y=12

y=12/12

y=1

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