8(y-4)=6y-42

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Solution for 8(y-4)=6y-42 equation: 



8(y-4)=6y-42

We move all terms to the left:

8(y-4)-(6y-42)=0

We multiply parentheses

8y-(6y-42)-32=0

We get rid of parentheses

8y-6y+42-32=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5

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