8(y-4)=7(y-2)

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Solution for 8(y-4)=7(y-2) equation:


Simplifying
8(y + -4) = 7(y + -2)

Reorder the terms:
8(-4 + y) = 7(y + -2)
(-4 * 8 + y * 8) = 7(y + -2)
(-32 + 8y) = 7(y + -2)

Reorder the terms:
-32 + 8y = 7(-2 + y)
-32 + 8y = (-2 * 7 + y * 7)
-32 + 8y = (-14 + 7y)

Solving
-32 + 8y = -14 + 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
-32 + 8y + -7y = -14 + 7y + -7y

Combine like terms: 8y + -7y = 1y
-32 + 1y = -14 + 7y + -7y

Combine like terms: 7y + -7y = 0
-32 + 1y = -14 + 0
-32 + 1y = -14

Add '32' to each side of the equation.
-32 + 32 + 1y = -14 + 32

Combine like terms: -32 + 32 = 0
0 + 1y = -14 + 32
1y = -14 + 32

Combine like terms: -14 + 32 = 18
1y = 18

Divide each side by '1'.
y = 18

Simplifying
y = 18

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