8(y-5)+2y=10

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Solution for 8(y-5)+2y=10 equation: 



8(y-5)+2y=10

We move all terms to the left:

8(y-5)+2y-(10)=0

We add all the numbers together, and all the variables

2y+8(y-5)-10=0

We multiply parentheses

2y+8y-40-10=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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