8(y-5)=2y+8

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Solution for 8(y-5)=2y+8 equation: 



8(y-5)=2y+8

We move all terms to the left:

8(y-5)-(2y+8)=0

We multiply parentheses

8y-(2y+8)-40=0

We get rid of parentheses

8y-2y-8-40=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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