8(y-6)+58=2(4y+5)

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Solution for 8(y-6)+58=2(4y+5) equation: 



8(y-6)+58=2(4y+5)

We move all terms to the left:

8(y-6)+58-(2(4y+5))=0

We multiply parentheses

8y-(2(4y+5))-48+58=0



We calculate terms in parentheses: -(2(4y+5)), so:

2(4y+5)

We multiply parentheses

8y+10

Back to the equation:

-(8y+10)



We add all the numbers together, and all the variables

8y-(8y+10)+10=0

We get rid of parentheses

8y-8y-10+10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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