8(y-7)-3(2y+2)=10

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Solution for 8(y-7)-3(2y+2)=10 equation: 


Simplifying
8(y + -7) + -3(2y + 2) = 10

Reorder the terms:
8(-7 + y) + -3(2y + 2) = 10
(-7 * 8 + y * 8) + -3(2y + 2) = 10
(-56 + 8y) + -3(2y + 2) = 10

Reorder the terms:
-56 + 8y + -3(2 + 2y) = 10
-56 + 8y + (2 * -3 + 2y * -3) = 10
-56 + 8y + (-6 + -6y) = 10

Reorder the terms:
-56 + -6 + 8y + -6y = 10

Combine like terms: -56 + -6 = -62
-62 + 8y + -6y = 10

Combine like terms: 8y + -6y = 2y
-62 + 2y = 10

Solving
-62 + 2y = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '62' to each side of the equation.
-62 + 62 + 2y = 10 + 62

Combine like terms: -62 + 62 = 0
0 + 2y = 10 + 62
2y = 10 + 62

Combine like terms: 10 + 62 = 72
2y = 72

Divide each side by '2'.
y = 36

Simplifying
y = 36

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