8(y-7)=(-2)(y+3)

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Solution for 8(y-7)=(-2)(y+3) equation: 



8(y-7)=(-2)(y+3)

We move all terms to the left:

8(y-7)-((-2)(y+3))=0

We multiply parentheses

8y-((-2)(y+3))-56=0

We multiply parentheses ..

8y-((-2y-6))-56=0



We calculate terms in parentheses: -((-2y-6)), so:

(-2y-6)

We get rid of parentheses

-2y-6

Back to the equation:

-(-2y-6)



We get rid of parentheses

8y+2y+6-56=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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