8(y-8)+4(y+8)-35=4y-6

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Solution for 8(y-8)+4(y+8)-35=4y-6 equation: 



8(y-8)+4(y+8)-35=4y-6

We move all terms to the left:

8(y-8)+4(y+8)-35-(4y-6)=0

We multiply parentheses

8y+4y-(4y-6)-64+32-35=0

We get rid of parentheses

8y+4y-4y+6-64+32-35=0

We add all the numbers together, and all the variables

8y-61=0

We move all terms containing y to the left, all other terms to the right

8y=61

y=61/8

y=7+5/8

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