8(y-9)=6(2y-12)-4y

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Solution for 8(y-9)=6(2y-12)-4y equation: 



8(y-9)=6(2y-12)-4y

We move all terms to the left:

8(y-9)-(6(2y-12)-4y)=0

We multiply parentheses

8y-(6(2y-12)-4y)-72=0



We calculate terms in parentheses: -(6(2y-12)-4y), so:

6(2y-12)-4y

We add all the numbers together, and all the variables

-4y+6(2y-12)

We multiply parentheses

-4y+12y-72

We add all the numbers together, and all the variables

8y-72

Back to the equation:

-(8y-72)



We get rid of parentheses

8y-8y+72-72=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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