8(z+1)-2(z-2)=3(Z-1)+2(z-3)

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Solution for 8(z+1)-2(z-2)=3(Z-1)+2(z-3) equation: 



8(z+1)-2(z-2)=3(-1)+2(z-3)

We move all terms to the left:

8(z+1)-2(z-2)-(3(-1)+2(z-3))=0

We multiply parentheses

8z-2z-(3(-1)+2(z-3))+8+4=0



We calculate terms in parentheses: -(3(-1)+2(z-3)), so:

3(-1)+2(z-3)

determiningTheFunctionDomain
2(z-3)+3(-1)

We add all the numbers together, and all the variables

2(z-3)-3

We multiply parentheses

2z-6-3

We add all the numbers together, and all the variables

2z-9

Back to the equation:

-(2z-9)



We add all the numbers together, and all the variables

6z-(2z-9)+12=0

We get rid of parentheses

6z-2z+9+12=0

We add all the numbers together, and all the variables

4z+21=0

We move all terms containing z to the left, all other terms to the right

4z=-21

z=-21/4

z=-5+1/4

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