8(z+1)=9z-5

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Solution for 8(z+1)=9z-5 equation:


Simplifying
8(z + 1) = 9z + -5

Reorder the terms:
8(1 + z) = 9z + -5
(1 * 8 + z * 8) = 9z + -5
(8 + 8z) = 9z + -5

Reorder the terms:
8 + 8z = -5 + 9z

Solving
8 + 8z = -5 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
8 + 8z + -9z = -5 + 9z + -9z

Combine like terms: 8z + -9z = -1z
8 + -1z = -5 + 9z + -9z

Combine like terms: 9z + -9z = 0
8 + -1z = -5 + 0
8 + -1z = -5

Add '-8' to each side of the equation.
8 + -8 + -1z = -5 + -8

Combine like terms: 8 + -8 = 0
0 + -1z = -5 + -8
-1z = -5 + -8

Combine like terms: -5 + -8 = -13
-1z = -13

Divide each side by '-1'.
z = 13

Simplifying
z = 13

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