8(z+2)-2(z-2)=2(z-4)+3(z-4)

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Solution for 8(z+2)-2(z-2)=2(z-4)+3(z-4) equation:


8(z+2)-2(z-2)=2(z-4)+3(z-4)

We simplify the equation to the form, which is simple to understand 
8(z+2)-2(z-2)=2(z-4)+3(z-4)

Reorder the terms in parentheses
+(+8z+16)-2*(z-2)=2*(z-4)+3*(z-4)

Remove unnecessary parentheses
+8z+16-2+*(+z-2+)=+2+*(+z-4+)+3+*(+z-4+)

Reorder the terms in parentheses
+8z+16+(-2z+4)=2*(z-4)+3*(z-4)

Remove unnecessary parentheses
+8z+16-2z+4=+2+*(+z-4+)+3+*(+z-4+)

Reorder the terms in parentheses
+8z+16-2z+4=+(+2z-8)+3*(z-4)

Remove unnecessary parentheses
+8z+16-2z+4=+2z-8+3+*(+z-4+)

Reorder the terms in parentheses
+8z+16-2z+4=+2z-8+(+3z-12)

Remove unnecessary parentheses
+8z+16-2z+4=+2z-8+3z-12

We move all terms containing z to the left and all other terms to the right. 
+8z-2z-2z-3z=-8-12-16-4

We simplify left and right side of the equation. 
+1z=-40

We divide both sides of the equation by 1 to get z. 
z=-40

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