8(z+2)-4(3z+1)=

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Solution for 8(z+2)-4(3z+1)= equation:


Simplifying
8(z + 2) + -4(3z + 1) = 0

Reorder the terms:
8(2 + z) + -4(3z + 1) = 0
(2 * 8 + z * 8) + -4(3z + 1) = 0
(16 + 8z) + -4(3z + 1) = 0

Reorder the terms:
16 + 8z + -4(1 + 3z) = 0
16 + 8z + (1 * -4 + 3z * -4) = 0
16 + 8z + (-4 + -12z) = 0

Reorder the terms:
16 + -4 + 8z + -12z = 0

Combine like terms: 16 + -4 = 12
12 + 8z + -12z = 0

Combine like terms: 8z + -12z = -4z
12 + -4z = 0

Solving
12 + -4z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -4z = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -4z = 0 + -12
-4z = 0 + -12

Combine like terms: 0 + -12 = -12
-4z = -12

Divide each side by '-4'.
z = 3

Simplifying
z = 3

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