8(z+2)=4(z+1)-12

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Solution for 8(z+2)=4(z+1)-12 equation: 



8(z+2)=4(z+1)-12

We move all terms to the left:

8(z+2)-(4(z+1)-12)=0

We multiply parentheses

8z-(4(z+1)-12)+16=0



We calculate terms in parentheses: -(4(z+1)-12), so:

4(z+1)-12

We multiply parentheses

4z+4-12

We add all the numbers together, and all the variables

4z-8

Back to the equation:

-(4z-8)



We get rid of parentheses

8z-4z+8+16=0

We add all the numbers together, and all the variables

4z+24=0

We move all terms containing z to the left, all other terms to the right

4z=-24

z=-24/4

z=-6

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