8(z+2)=4(z+1)-20

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Solution for 8(z+2)=4(z+1)-20 equation: 


Simplifying
8(z + 2) = 4(z + 1) + -20

Reorder the terms:
8(2 + z) = 4(z + 1) + -20
(2 * 8 + z * 8) = 4(z + 1) + -20
(16 + 8z) = 4(z + 1) + -20

Reorder the terms:
16 + 8z = 4(1 + z) + -20
16 + 8z = (1 * 4 + z * 4) + -20
16 + 8z = (4 + 4z) + -20

Reorder the terms:
16 + 8z = 4 + -20 + 4z

Combine like terms: 4 + -20 = -16
16 + 8z = -16 + 4z

Solving
16 + 8z = -16 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
16 + 8z + -4z = -16 + 4z + -4z

Combine like terms: 8z + -4z = 4z
16 + 4z = -16 + 4z + -4z

Combine like terms: 4z + -4z = 0
16 + 4z = -16 + 0
16 + 4z = -16

Add '-16' to each side of the equation.
16 + -16 + 4z = -16 + -16

Combine like terms: 16 + -16 = 0
0 + 4z = -16 + -16
4z = -16 + -16

Combine like terms: -16 + -16 = -32
4z = -32

Divide each side by '4'.
z = -8

Simplifying
z = -8

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