8(z+2)=5(2+1)-13

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Solution for 8(z+2)=5(2+1)-13 equation: 


Simplifying
8(z + 2) = 5(2 + 1) + -13

Reorder the terms:
8(2 + z) = 5(2 + 1) + -13
(2 * 8 + z * 8) = 5(2 + 1) + -13
(16 + 8z) = 5(2 + 1) + -13

Combine like terms: 2 + 1 = 3
16 + 8z = 5(3) + -13

Multiply 5 * 3
16 + 8z = 15 + -13

Combine like terms: 15 + -13 = 2
16 + 8z = 2

Solving
16 + 8z = 2

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 8z = 2 + -16

Combine like terms: 16 + -16 = 0
0 + 8z = 2 + -16
8z = 2 + -16

Combine like terms: 2 + -16 = -14
8z = -14

Divide each side by '8'.
z = -1.75

Simplifying
z = -1.75

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