8(z+2)=5(z-4)

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Solution for 8(z+2)=5(z-4) equation: 



8(z+2)=5(z-4)

We move all terms to the left:

8(z+2)-(5(z-4))=0

We multiply parentheses

8z-(5(z-4))+16=0



We calculate terms in parentheses: -(5(z-4)), so:

5(z-4)

We multiply parentheses

5z-20

Back to the equation:

-(5z-20)



We get rid of parentheses

8z-5z+20+16=0

We add all the numbers together, and all the variables

3z+36=0

We move all terms containing z to the left, all other terms to the right

3z=-36

z=-36/3

z=-12

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