8(z+3)-2(z-4)=3(z-2)+2(z-3)

Solution for 8(z+3)-2(z-4)=3(z-2)+2(z-3) equation:

8(z+3)-2(z-4)=3(z-2)+2(z-3)

We simplify the equation to the form, which is simple to understand 
8(z+3)-2(z-4)=3(z-2)+2(z-3)

Reorder the terms in parentheses
+(+8z+24)-2*(z-4)=3*(z-2)+2*(z-3)

Remove unnecessary parentheses
+8z+24-2+*(+z-4+)=+3+*(+z-2+)+2+*(+z-3+)

Reorder the terms in parentheses
+8z+24+(-2z+8)=3*(z-2)+2*(z-3)

Remove unnecessary parentheses
+8z+24-2z+8=+3+*(+z-2+)+2+*(+z-3+)

Reorder the terms in parentheses
+8z+24-2z+8=+(+3z-6)+2*(z-3)

Remove unnecessary parentheses
+8z+24-2z+8=+3z-6+2+*(+z-3+)

Reorder the terms in parentheses
+8z+24-2z+8=+3z-6+(+2z-6)

Remove unnecessary parentheses
+8z+24-2z+8=+3z-6+2z-6

We move all terms containing z to the left and all other terms to the right. 
+8z-2z-3z-2z=-6-6-24-8

We simplify left and right side of the equation. 
+1z=-44

We divide both sides of the equation by 1 to get z. 
z=-44