8(z+4)=-7(z+-4)+-3

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Solution for 8(z+4)=-7(z+-4)+-3 equation: 



8(z+4)=-7(z+-4)+-3

We move all terms to the left:

8(z+4)-(-7(z+-4)+-3)=0

We add all the numbers together, and all the variables

8(z+4)-(-7(z-4)+-3)=0

We use the square of the difference formula

8(z+4)-(-7(z-4)-3)=0

We multiply parentheses

8z-(-7(z-4)-3)+32=0



We calculate terms in parentheses: -(-7(z-4)-3), so:

-7(z-4)-3

We multiply parentheses

-7z+28-3

We add all the numbers together, and all the variables

-7z+25

Back to the equation:

-(-7z+25)



We get rid of parentheses

8z+7z-25+32=0

We add all the numbers together, and all the variables

15z+7=0

We move all terms containing z to the left, all other terms to the right

15z=-7

z=-7/15

z=-7/15

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