8(z+5)=(z-2)

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Solution for 8(z+5)=(z-2) equation: 



8(z+5)=(z-2)

We move all terms to the left:

8(z+5)-((z-2))=0

We multiply parentheses

8z-((z-2))+40=0



We calculate terms in parentheses: -((z-2)), so:

(z-2)

We get rid of parentheses

z-2

Back to the equation:

-(z-2)



We get rid of parentheses

8z-z+2+40=0

We add all the numbers together, and all the variables

7z+42=0

We move all terms containing z to the left, all other terms to the right

7z=-42

z=-42/7

z=-6

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