8(z+5)=7(z-2)+z

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Solution for 8(z+5)=7(z-2)+z equation:



8(z+5)=7(z-2)+z
We move all terms to the left:
8(z+5)-(7(z-2)+z)=0
We multiply parentheses
8z-(7(z-2)+z)+40=0
We calculate terms in parentheses: -(7(z-2)+z), so:
7(z-2)+z
We add all the numbers together, and all the variables
z+7(z-2)
We multiply parentheses
z+7z-14
We add all the numbers together, and all the variables
8z-14
Back to the equation:
-(8z-14)
We get rid of parentheses
8z-8z+14+40=0
We add all the numbers together, and all the variables
54!=0
There is no solution for this equation

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