8(z+5)=7(z-4)+z

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Solution for 8(z+5)=7(z-4)+z equation:


Simplifying
8(z + 5) = 7(z + -4) + z

Reorder the terms:
8(5 + z) = 7(z + -4) + z
(5 * 8 + z * 8) = 7(z + -4) + z
(40 + 8z) = 7(z + -4) + z

Reorder the terms:
40 + 8z = 7(-4 + z) + z
40 + 8z = (-4 * 7 + z * 7) + z
40 + 8z = (-28 + 7z) + z

Combine like terms: 7z + z = 8z
40 + 8z = -28 + 8z

Add '-8z' to each side of the equation.
40 + 8z + -8z = -28 + 8z + -8z

Combine like terms: 8z + -8z = 0
40 + 0 = -28 + 8z + -8z
40 = -28 + 8z + -8z

Combine like terms: 8z + -8z = 0
40 = -28 + 0
40 = -28

Solving
40 = -28

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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