8(z-10)=48

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Solution for 8(z-10)=48 equation: 



8(z-10)=48

We move all terms to the left:

8(z-10)-(48)=0

We multiply parentheses

8z-80-48=0

We add all the numbers together, and all the variables

8z-128=0

We move all terms containing z to the left, all other terms to the right

8z=128

z=128/8

z=16

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