8(z-3)+z=9(z-4)+12

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Solution for 8(z-3)+z=9(z-4)+12 equation: 


Simplifying
8(z + -3) + z = 9(z + -4) + 12

Reorder the terms:
8(-3 + z) + z = 9(z + -4) + 12
(-3 * 8 + z * 8) + z = 9(z + -4) + 12
(-24 + 8z) + z = 9(z + -4) + 12

Combine like terms: 8z + z = 9z
-24 + 9z = 9(z + -4) + 12

Reorder the terms:
-24 + 9z = 9(-4 + z) + 12
-24 + 9z = (-4 * 9 + z * 9) + 12
-24 + 9z = (-36 + 9z) + 12

Reorder the terms:
-24 + 9z = -36 + 12 + 9z

Combine like terms: -36 + 12 = -24
-24 + 9z = -24 + 9z

Add '24' to each side of the equation.
-24 + 24 + 9z = -24 + 24 + 9z

Combine like terms: -24 + 24 = 0
0 + 9z = -24 + 24 + 9z
9z = -24 + 24 + 9z

Combine like terms: -24 + 24 = 0
9z = 0 + 9z
9z = 9z

Add '-9z' to each side of the equation.
9z + -9z = 9z + -9z

Combine like terms: 9z + -9z = 0
0 = 9z + -9z

Combine like terms: 9z + -9z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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