8(z-5)=7(-2z+10)

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Solution for 8(z-5)=7(-2z+10) equation: 



8(z-5)=7(-2z+10)

We move all terms to the left:

8(z-5)-(7(-2z+10))=0

We multiply parentheses

8z-(7(-2z+10))-40=0



We calculate terms in parentheses: -(7(-2z+10)), so:

7(-2z+10)

We multiply parentheses

-14z+70

Back to the equation:

-(-14z+70)



We get rid of parentheses

8z+14z-70-40=0

We add all the numbers together, and all the variables

22z-110=0

We move all terms containing z to the left, all other terms to the right

22z=110

z=110/22

z=5

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