8(z-6)=4+2z

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Solution for 8(z-6)=4+2z equation: 



8(z-6)=4+2z

We move all terms to the left:

8(z-6)-(4+2z)=0

We add all the numbers together, and all the variables

8(z-6)-(2z+4)=0

We multiply parentheses

8z-(2z+4)-48=0

We get rid of parentheses

8z-2z-4-48=0

We add all the numbers together, and all the variables

6z-52=0

We move all terms containing z to the left, all other terms to the right

6z=52

z=52/6

z=8+2/3

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