8*(y+3)=4*(y-1)

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Solution for 8*(y+3)=4*(y-1) equation: 



8(y+3)=4(y-1)

We move all terms to the left:

8(y+3)-(4(y-1))=0

We multiply parentheses

8y-(4(y-1))+24=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

8y-4y+4+24=0

We add all the numbers together, and all the variables

4y+28=0

We move all terms containing y to the left, all other terms to the right

4y=-28

y=-28/4

y=-7

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