8*x+1-4(x-3)=2(x+18)+x

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Solution for 8*x+1-4(x-3)=2(x+18)+x equation: 



8x+1-4(x-3)=2(x+18)+x

We move all terms to the left:

8x+1-4(x-3)-(2(x+18)+x)=0

We multiply parentheses

8x-4x-(2(x+18)+x)+12+1=0



We calculate terms in parentheses: -(2(x+18)+x), so:

2(x+18)+x

We add all the numbers together, and all the variables

x+2(x+18)

We multiply parentheses

x+2x+36

We add all the numbers together, and all the variables

3x+36

Back to the equation:

-(3x+36)



We add all the numbers together, and all the variables

4x-(3x+36)+13=0

We get rid of parentheses

4x-3x-36+13=0

We add all the numbers together, and all the variables

x-23=0

We move all terms containing x to the left, all other terms to the right

x=23

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