8*x-2(x+1)=2(3x-1)

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Solution for 8*x-2(x+1)=2(3x-1) equation:


Simplifying
8x + -2(x + 1) = 2(3x + -1)

Reorder the terms:
8x + -2(1 + x) = 2(3x + -1)
8x + (1 * -2 + x * -2) = 2(3x + -1)
8x + (-2 + -2x) = 2(3x + -1)

Reorder the terms:
-2 + 8x + -2x = 2(3x + -1)

Combine like terms: 8x + -2x = 6x
-2 + 6x = 2(3x + -1)

Reorder the terms:
-2 + 6x = 2(-1 + 3x)
-2 + 6x = (-1 * 2 + 3x * 2)
-2 + 6x = (-2 + 6x)

Add '2' to each side of the equation.
-2 + 2 + 6x = -2 + 2 + 6x

Combine like terms: -2 + 2 = 0
0 + 6x = -2 + 2 + 6x
6x = -2 + 2 + 6x

Combine like terms: -2 + 2 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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