8+(2x+1)+(2x+1)=0

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Solution for 8+(2x+1)+(2x+1)=0 equation:


Simplifying
8 + (2x + 1) + (2x + 1) = 0

Reorder the terms:
8 + (1 + 2x) + (2x + 1) = 0

Remove parenthesis around (1 + 2x)
8 + 1 + 2x + (2x + 1) = 0

Reorder the terms:
8 + 1 + 2x + (1 + 2x) = 0

Remove parenthesis around (1 + 2x)
8 + 1 + 2x + 1 + 2x = 0

Reorder the terms:
8 + 1 + 1 + 2x + 2x = 0

Combine like terms: 8 + 1 = 9
9 + 1 + 2x + 2x = 0

Combine like terms: 9 + 1 = 10
10 + 2x + 2x = 0

Combine like terms: 2x + 2x = 4x
10 + 4x = 0

Solving
10 + 4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 4x = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 4x = 0 + -10
4x = 0 + -10

Combine like terms: 0 + -10 = -10
4x = -10

Divide each side by '4'.
x = -2.5

Simplifying
x = -2.5

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