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8+(4x)=5-(x/2)
We move all terms to the left:
8+(4x)-(5-(x/2))=0
We add all the numbers together, and all the variables
4x-(5-(+x/2))+8=0
We multiply all the terms by the denominator
4x*2))-(5-(+x+8*2))=0
We add all the numbers together, and all the variables
4x*2))-(5-(x+16))=0
We add all the numbers together, and all the variables
4x*2))-(5-(x=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{16}=0$
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