8+(5/(v-1))=7/(v+2)

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Solution for 8+(5/(v-1))=7/(v+2) equation:


D( v )

v-1 = 0

v+2 = 0

v-1 = 0

v-1 = 0

v-1 = 0 // + 1

v = 1

v+2 = 0

v+2 = 0

v+2 = 0 // - 2

v = -2

v in (-oo:-2) U (-2:1) U (1:+oo)

5/(v-1)+8 = 7/(v+2) // - 7/(v+2)

5/(v-1)-(7/(v+2))+8 = 0

5/(v-1)-7*(v+2)^-1+8 = 0

5/(v-1)-7/(v+2)+8 = 0

(5*(v+2))/((v-1)*(v+2))+(-7*(v-1))/((v-1)*(v+2))+(8*(v-1)*(v+2))/((v-1)*(v+2)) = 0

5*(v+2)-7*(v-1)+8*(v-1)*(v+2) = 0

8*v^2-2*v+8*v-16+17 = 0

8*v^2+6*v+1 = 0

8*v^2+6*v+1 = 0

8*v^2+6*v+1 = 0

DELTA = 6^2-(1*4*8)

DELTA = 4

DELTA > 0

v = (4^(1/2)-6)/(2*8) or v = (-4^(1/2)-6)/(2*8)

v = -1/4 or v = -1/2

(v+1/2)*(v+1/4) = 0

((v+1/2)*(v+1/4))/((v-1)*(v+2)) = 0

((v+1/2)*(v+1/4))/((v-1)*(v+2)) = 0 // * (v-1)*(v+2)

(v+1/2)*(v+1/4) = 0

( v+1/2 )

v+1/2 = 0 // - 1/2

v = -1/2

( v+1/4 )

v+1/4 = 0 // - 1/4

v = -1/4

v in { -1/2, -1/4 }

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