8+(b+4)=4-(b-1)

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Solution for 8+(b+4)=4-(b-1) equation: 



8+(b+4)=4-(b-1)

We move all terms to the left:

8+(b+4)-(4-(b-1))=0

We get rid of parentheses

b-(4-(b-1))+4+8=0



We calculate terms in parentheses: -(4-(b-1)), so:

4-(b-1)

determiningTheFunctionDomain
-(b-1)+4

We get rid of parentheses

-b+1+4

We add all the numbers together, and all the variables

-1b+5

Back to the equation:

-(-1b+5)



We add all the numbers together, and all the variables

b-(-1b+5)+12=0

We get rid of parentheses

b+1b-5+12=0

We add all the numbers together, and all the variables

2b+7=0

We move all terms containing b to the left, all other terms to the right

2b=-7

b=-7/2

b=-3+1/2

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