8+(c+1)=5c-(c+c)

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Solution for 8+(c+1)=5c-(c+c) equation: 



8+(c+1)=5c-(c+c)

We move all terms to the left:

8+(c+1)-(5c-(c+c))=0

We add all the numbers together, and all the variables

(c+1)-(5c-(+2c))+8=0

We get rid of parentheses

c-(5c-(+2c))+1+8=0



We calculate terms in parentheses: -(5c-(+2c)), so:

5c-(+2c)

We get rid of parentheses

5c-2c

We add all the numbers together, and all the variables

3c

Back to the equation:

-(3c)



We add all the numbers together, and all the variables

-2c+9=0

We move all terms containing c to the left, all other terms to the right

-2c=-9

c=-9/-2

c=4+1/2

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