8+(x-4)=6-(x+5)

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Solution for 8+(x-4)=6-(x+5) equation: 



8+(x-4)=6-(x+5)

We move all terms to the left:

8+(x-4)-(6-(x+5))=0

We get rid of parentheses

x-(6-(x+5))-4+8=0



We calculate terms in parentheses: -(6-(x+5)), so:

6-(x+5)

determiningTheFunctionDomain
-(x+5)+6

We get rid of parentheses

-x-5+6

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We add all the numbers together, and all the variables

x-(-1x+1)+4=0

We get rid of parentheses

x+1x-1+4=0

We add all the numbers together, and all the variables

2x+3=0

We move all terms containing x to the left, all other terms to the right

2x=-3

x=-3/2

x=-1+1/2

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