8+11(y-2)=-2+13(y+4)+10

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Solution for 8+11(y-2)=-2+13(y+4)+10 equation: 



8+11(y-2)=-2+13(y+4)+10

We move all terms to the left:

8+11(y-2)-(-2+13(y+4)+10)=0

We multiply parentheses

11y-(-2+13(y+4)+10)-22+8=0



We calculate terms in parentheses: -(-2+13(y+4)+10), so:

-2+13(y+4)+10

determiningTheFunctionDomain
13(y+4)-2+10

We add all the numbers together, and all the variables

13(y+4)+8

We multiply parentheses

13y+52+8

We add all the numbers together, and all the variables

13y+60

Back to the equation:

-(13y+60)



We add all the numbers together, and all the variables

11y-(13y+60)-14=0

We get rid of parentheses

11y-13y-60-14=0

We add all the numbers together, and all the variables

-2y-74=0

We move all terms containing y to the left, all other terms to the right

-2y=74

y=74/-2

y=-37

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