8+2(3v-6)=-7(2v-2)+8v

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Solution for 8+2(3v-6)=-7(2v-2)+8v equation: 



8+2(3v-6)=-7(2v-2)+8v

We move all terms to the left:

8+2(3v-6)-(-7(2v-2)+8v)=0

We multiply parentheses

6v-(-7(2v-2)+8v)-12+8=0



We calculate terms in parentheses: -(-7(2v-2)+8v), so:

-7(2v-2)+8v

We add all the numbers together, and all the variables

8v-7(2v-2)

We multiply parentheses

8v-14v+14

We add all the numbers together, and all the variables

-6v+14

Back to the equation:

-(-6v+14)



We add all the numbers together, and all the variables

6v-(-6v+14)-4=0

We get rid of parentheses

6v+6v-14-4=0

We add all the numbers together, and all the variables

12v-18=0

We move all terms containing v to the left, all other terms to the right

12v=18

v=18/12

v=1+1/2

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