8+2(3x-3)=-3(-4x-2)+8

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Solution for 8+2(3x-3)=-3(-4x-2)+8 equation:



8+2(3x-3)=-3(-4x-2)+8
We move all terms to the left:
8+2(3x-3)-(-3(-4x-2)+8)=0
We multiply parentheses
6x-(-3(-4x-2)+8)-6+8=0
We calculate terms in parentheses: -(-3(-4x-2)+8), so:
-3(-4x-2)+8
We multiply parentheses
12x+6+8
We add all the numbers together, and all the variables
12x+14
Back to the equation:
-(12x+14)
We add all the numbers together, and all the variables
6x-(12x+14)+2=0
We get rid of parentheses
6x-12x-14+2=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2

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