8+2(3x-5)=9-4(2x+1)

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Solution for 8+2(3x-5)=9-4(2x+1) equation: 



8+2(3x-5)=9-4(2x+1)

We move all terms to the left:

8+2(3x-5)-(9-4(2x+1))=0

We multiply parentheses

6x-(9-4(2x+1))-10+8=0



We calculate terms in parentheses: -(9-4(2x+1)), so:

9-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+9

We multiply parentheses

-8x-4+9

We add all the numbers together, and all the variables

-8x+5

Back to the equation:

-(-8x+5)



We add all the numbers together, and all the variables

6x-(-8x+5)-2=0

We get rid of parentheses

6x+8x-5-2=0

We add all the numbers together, and all the variables

14x-7=0

We move all terms containing x to the left, all other terms to the right

14x=7

x=7/14

x=1/2

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