8+2(4u-4)=-4(3u-3)+4u

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Solution for 8+2(4u-4)=-4(3u-3)+4u equation: 



8+2(4u-4)=-4(3u-3)+4u

We move all terms to the left:

8+2(4u-4)-(-4(3u-3)+4u)=0

We multiply parentheses

8u-(-4(3u-3)+4u)-8+8=0



We calculate terms in parentheses: -(-4(3u-3)+4u), so:

-4(3u-3)+4u

We add all the numbers together, and all the variables

4u-4(3u-3)

We multiply parentheses

4u-12u+12

We add all the numbers together, and all the variables

-8u+12

Back to the equation:

-(-8u+12)



We add all the numbers together, and all the variables

8u-(-8u+12)=0

We get rid of parentheses

8u+8u-12=0

We add all the numbers together, and all the variables

16u-12=0

We move all terms containing u to the left, all other terms to the right

16u=12

u=12/16

u=3/4

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