8+2(4v-2)=-2(3v-1)+8v

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Solution for 8+2(4v-2)=-2(3v-1)+8v equation: 



8+2(4v-2)=-2(3v-1)+8v

We move all terms to the left:

8+2(4v-2)-(-2(3v-1)+8v)=0

We multiply parentheses

8v-(-2(3v-1)+8v)-4+8=0



We calculate terms in parentheses: -(-2(3v-1)+8v), so:

-2(3v-1)+8v

We add all the numbers together, and all the variables

8v-2(3v-1)

We multiply parentheses

8v-6v+2

We add all the numbers together, and all the variables

2v+2

Back to the equation:

-(2v+2)



We add all the numbers together, and all the variables

8v-(2v+2)+4=0

We get rid of parentheses

8v-2v-2+4=0

We add all the numbers together, and all the variables

6v+2=0

We move all terms containing v to the left, all other terms to the right

6v=-2

v=-2/6

v=-1/3

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