8+2(7u-6)=-2(3u-7)+4u

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Solution for 8+2(7u-6)=-2(3u-7)+4u equation: 



8+2(7u-6)=-2(3u-7)+4u

We move all terms to the left:

8+2(7u-6)-(-2(3u-7)+4u)=0

We multiply parentheses

14u-(-2(3u-7)+4u)-12+8=0



We calculate terms in parentheses: -(-2(3u-7)+4u), so:

-2(3u-7)+4u

We add all the numbers together, and all the variables

4u-2(3u-7)

We multiply parentheses

4u-6u+14

We add all the numbers together, and all the variables

-2u+14

Back to the equation:

-(-2u+14)



We add all the numbers together, and all the variables

14u-(-2u+14)-4=0

We get rid of parentheses

14u+2u-14-4=0

We add all the numbers together, and all the variables

16u-18=0

We move all terms containing u to the left, all other terms to the right

16u=18

u=18/16

u=1+1/8

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